1. Which one of the
following substrates should be used to provide large gain and BW of MSA for
same substrate thickness?
RT
Duroid 6010 (εr = 10.2, tan δ= 0.0023)
Glass
Epoxy FR-4 (εr = 4.4, tan δ = 0.02)
RT
Duroid 5880 (εr = 2.2, tan δ = 0.0009)
Air
(εr = 1, tan δ = 0)
Ans: d
Common data for
Questions 2 to 6: A
rectangular microstrip antenna (RMSA) is designed at 1800 MHz on a substrate
having εr = 2.33, h = 1.6 mm and tan δ = 0.0012.
2. Width of the RMSA is:
8.33
cm
6.46
cm
4.17
cm
3.34
cm
Ans: b
3. The effective
dielectric constant seen by the RMSA is:
3.15
2.33
2.26
2.0
Ans: c
4. Length of the RMSA is:
6.46
cm
6.05
cm
5.33
cm
5.14
cm
Ans: c
5. For 50Ω input
impedance, approximate location of the feed-point from the centre of RMSA is:
0.5
cm
1.0
cm
1.5
cm
2.0
cm
Ans: b
6. Approximate gain of
the RMSA should be in the range:
3-5
dBi
5-7
dBi
7-9
dBi
9-11
dBi
Ans: d
7. To realize n-way power
divider, circular microstrip patch should be excited in ___mode.
TM11
TM21
TM01
TM02
Ans: d
Common data for
Questions 8 to 10: An air suspended
circular microstrip antenna is designed to resonate at 2.45 GHz as shown in
Fig.1. The suspended substrate parameters are: εr = 4.4, h =
0.16 cm and tan δ = 0.02, and the air-gap Δ = 0.6
8. The equivalent
dielectric constant seen by the antenna is:
2.83
2.24
1.86
1.19
Ans: d
9. Approximate radius of
the suspended circular MSA is:
3.86
cm
2.86
cm
1.92
cm
1.16
cm
Ans: b
10. Approximate gain of
the antenna is in the range:
4-6
dBi
6-8
dBi
10-12dBi
Ans: c
0 comments:
Post a Comment